1 条题解
-
0
C++ :
#include <cstdio> int main(){ int M, N; if(scanf("%d %d", &M, &N) != 2) return 0; int d = N - M; if(d <= 0){ printf("0\n"); return 0; } if(d == 1){ printf("1\n"); return 0; } unsigned long long a = 1, b = 2; /* f(1), f(2) */ for(int i = 3; i <= d; i++){ unsigned long long c = a + b; a = b; b = c; } printf("%llu\n", b); return 0; }
- 1
信息
- ID
- 2666
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者